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  1. 以ATM引出DBMS 2. MySQL

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    - 客户端
    1. 通信交流
      • 授权
      • SQL语句
        • 数据库 create database db1 default charset=utf8; drop database db1;
        • 数据表 先创建tb2部门表 create table tb1用户表( id int not null auto_increment primary key, name char(10), department_id int, p_id int, constraint fk_1 foreign key (department_id,p_id) references tb2(tid,xid) )engine=innodb default charset=utf8; 补充:主键 一个表只能有一个主键 主键可以由多列组成 补充:外键 ? CREATE TABLE t5 ( nid int(11) NOT NULL AUTO_INCREMENT, pid int(11) not NULL, num int(11), primary key(nid,pid) ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
                create table t6(
    id int auto_increment primary key,
    name char(10),
    id1 int,
    id2 int,
    CONSTRAINT fk_t5_t6 foreign key (id1,id2) REFERENCES t1(nid,pid)
    )engine=innodb default charset=utf8;



    - 数据行

    insert into tb1(name,age) values('alex',18);
    insert into tb1(name,age) values('alex',18),('egon',19),('yuan',20);

    delete from tb1;
    truncate table tb1;
    delete from tb1 where id > 10


    update tb1 set name='root' where id > 10

    select * from tb;
    select id,name from tb;


    4 对于自增补充: desc t10;

    show create table t10;

    show create table t10 \G;

    alter table t10 AUTO_INCREMENT=20;


    MySQL: 自增步长
    基于会话级别:
    show session variables like 'auto_inc%'; 查看全局变量
    set session auto_increment_increment=2; 设置会话步长
    # set session auto_increment_offset=10;
    基于全局级别:
    show global variables like 'auto_inc%'; 查看全局变量
    set global auto_increment_increment=2; 设置会话步长
    # set global auto_increment_offset=10;


    SqlServer:自增步长:
    基础表级别:
    CREATE TABLE `t5` (
    `nid` int(11) NOT NULL AUTO_INCREMENT,
    `pid` int(11) NOT NULL,
    `num` int(11) DEFAULT NULL,
    PRIMARY KEY (`nid`,`pid`)
    ) ENGINE=InnoDB AUTO_INCREMENT=4, 步长=2 DEFAULT CHARSET=utf8

    CREATE TABLE `t6` (
    `nid` int(11) NOT NULL AUTO_INCREMENT,
    `pid` int(11) NOT NULL,
    `num` int(11) DEFAULT NULL,
    PRIMARY KEY (`nid`,`pid`)
    ) ENGINE=InnoDB AUTO_INCREMENT=4, 步长=20 DEFAULT CHARSET=utf8


今日内容: 0. 唯一索引

    create table t1(
id int ....,
num int,
xx int,
unique 唯一索引名称 (列名,列名),
constraint ....
)
#
1 1 1
2 1 2
PS:
唯一:
约束不能重复(可以为空)
PS: 主键不能重复(不能为空)
加速查找

1. 外键的变种

a. 用户表和部门表

用户:
1 alex 1
2 root 1
3 egon 2
4 laoyao 3

部门:
1 服务
2 保安
3 公关
===》 一对多
b. 用户表和博客表
用户表:
1 alex
2 root
3 egon
4 laoyao
博客表:
FK() + 唯一
1 /yuanchenqi/ 4
2 /alex3714/ 1
3 /asdfasdf/ 3
4 /ffffffff/ 2

===> 一对一

create table userinfo1(
id int auto_increment primary key,
name char(10),
gender char(10),
email varchar(64)
)engine=innodb default charset=utf8;

create table admin(
id int not null auto_increment primary key,
username varchar(64) not null,
password VARCHAR(64) not null,
user_id int not null,
unique uq_u1 (user_id),
CONSTRAINT fk_admin_u1 FOREIGN key (user_id) REFERENCES userinfo1(id)
)engine=innodb default charset=utf8;




c. 用户表(百合网) 相亲记录表

示例1:
用户表
相亲表

示例2:
用户表
主机表
用户主机关系表
===》多对多

create table userinfo2(
id int auto_increment primary key,
name char(10),
gender char(10),
email varchar(64)
)engine=innodb default charset=utf8;

create table host(
id int auto_increment primary key,
hostname char(64)
)engine=innodb default charset=utf8;


create table user2host(
id int auto_increment primary key,
userid int not null,
hostid int not null,
unique uq_user_host (userid,hostid),
CONSTRAINT fk_u2h_user FOREIGN key (userid) REFERENCES userinfo2(id),
CONSTRAINT fk_u2h_host FOREIGN key (hostid) REFERENCES host(id)
)engine=innodb default charset=utf8;


2. SQL语句数据行操作补充
create table tb12(
id int auto_increment primary key,
name varchar(32),
age int
)engine=innodb default charset=utf8;


insert into tb11(name,age) values('alex',12);

insert into tb11(name,age) values('alex',12),('root',18);

insert into tb12(name,age) select name,age from tb11;

delete from tb12;
delete from tb12 where id !=2
delete from tb12 where id =2
delete from tb12 where id > 2
delete from tb12 where id >=2
delete from tb12 where id >=2 or name='alex'


update tb12 set name='alex' where id>12 and name='xx'
update tb12 set name='alex',age=19 where id>12 and name='xx'


select * from tb12;

select id,name from tb12;

select id,name from tb12 where id > 10 or name ='xxx';

select id,name as cname from tb12 where id > 10 or name ='xxx';

select name,age,11 from tb12;

其他:
select * from tb12 where id != 1
select * from tb12 where id in (1,5,12);
select * from tb12 where id not in (1,5,12);
select * from tb12 where id in (select id from tb11)
select * from tb12 where id between 5 and 12;


通配符:

select * from tb12 where name like "a%"
select * from tb12 where name like "a_"


分页:

select * from tb12 limit 10;

select * from tb12 limit 0,10;
select * from tb12 limit 10,10;
select * from tb12 limit 20,10;

select * from tb12 limit 10 offset 20;
从第20行开始读取,读取10行;

结合Python分页:
# page = input('请输入要查看的页码')
# page = int(page)
# (page-1) * 10
# select * from tb12 limit 0,10; 1
# select * from tb12 limit 10,10;2


排序:
select * from tb12 order by id desc; 大到小
select * from tb12 order by id asc; 小到大
select * from tb12 order by age desc,id desc;

取后10条数据
select * from tb12 order by id desc limit 10;

分组:

select count(id),max(id),part_id from userinfo5 group by part_id;

count
max
min
sum
avg

**** 如果对于聚合函数结果进行二次筛选时?必须使用having ****
select count(id),part_id from userinfo5 group by part_id having count(id) > 1;

select count(id),part_id from userinfo5 where id > 0 group by part_id having count(id) > 1;


连表操作:

select * from userinfo5,department5

select * from userinfo5,department5 where userinfo5.part_id = department5.id


select * from userinfo5 left join department5 on userinfo5.part_id = department5.id
select * from department5 left join userinfo5 on userinfo5.part_id = department5.id
# userinfo5左边全部显示


# select * from userinfo5 right join department5 on userinfo5.part_id = department5.id
# department5右边全部显示



select * from userinfo5 innder join department5 on userinfo5.part_id = department5.id
将出现null时一行隐藏






select * from
department5
left join userinfo5 on userinfo5.part_id = department5.id
left join userinfo6 on userinfo5.part_id = department5.id


select
score.sid,
student.sid
from
score

left join student on score.student_id = student.sid

left join course on score.course_id = course.cid

left join class on student.class_id = class.cid

left join teacher on course.teacher_id=teacher.tid




select count(id) from userinfo5;